Nachricht 3-misol

1. März 2022

3-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=(1+y)*(x+y*1./(x*x+4))*1./(exp(-(x+2))+sqrt(x*x+4)); B=(1+pow(tan(A*M_PI*1./2),2))*pow((x*x+4),1./5); cout<<"A= "<<A<<endl<<"B= "<<B; return 0; }

08:56

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Kolleriya__08:381-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=(sqrt(fabs(x-1)-pow(fabs(y),1./3)))*1./(1+pow(x,2)*1./2+log((y K

Kolleriya__08:522-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=(3+exp(y-x))*1./(1+x*x*(y-cos(x-3))); B=1+sqrt(fabs(y-x))+pow(

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Kolleriya__09:004-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=y+x*1./(x*x+fabs((x*x)*1./(exp(y)+(x*x*x)*1./3))); B=(1+cos(A-K

Kolleriya__09:01Rustamov misol ishlayapsizmi??