Fil de discussionMessage n° 8339

1-misolda B=davomida edarajasi arctgni burchagimi

1-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=(sqrt(fabs(x-1)-pow(fabs(y),1./3)))*1./(1+pow(x,2)*1./2+log((y*y)*1./4)); B=x*(atan(A)+exp(-(x-1))); cout<<"A= "<<A<<endl<<"B= "<<B; return 0; }

2-misol #include <bits/stdc++.h> using namespace std; int main() { float A, B, x, y; cin>>x>>y; A=(3+exp(y-x))*1./(1+x*x*(y-cos(x-3))); B=1+sqrt(fabs(y-x))+pow((y-A),2)*1./2*pow((y-x),1./3); cout<<"A= "<<A<<endl<<"B= "<<B; return 0; }