简体中文
Telegram

帖子def maxSumOfNonAdjacentNodes(cls, input1, input2):

2025年9月15日
D
Deloitte | COGNIZANT | IBM | CAPGEMINI
def maxSumOfNonAdjacentNodes(cls, input1, input2): a = input2 n = len(a) if n == 0: return 0 eff = [0]*n for i in range(n): penalty = a[i-1] if i > 0 and a[i-1] < 0 else 0 eff[i] = a[i] + penalty def nz(x): return x if x > 0 else 0 if n == 1: return nz(eff[0]) if n == 2: return max(nz(eff[0]), nz(eff[1])) prev2 = nz(eff[0]) prev1 = max(prev2, nz(eff[1])) for i in range(2, n): take = prev2 + nz(eff[i]) skip = prev1 cur = take if take > skip else skip prev2, prev1 = prev1, cur return prev1 //MAX REWARD POINTS✅ VIRTUSA✅
667 ·

信息流中的邻近内容

DDeloitte | COGNIZANT | IBM | CAPGEMINIIBM CIC✅ Contact : @MLCODER2DDeloitte | COGNIZANT | IBM | CAPGEMINIdef legoString(input1, input2, input3): wall = input1 n = input2 blocks = input3 if not wall or not blocks: return [-1] word_len = len(blocks[0]) if len(wall) <
这条消息
DDeloitte | COGNIZANT | IBM | CAPGEMINIfrom collections import deque def minMovesToHospital(cls, input1, input2, input3): N = input1 E = input2 K = input3 - 1 if E[K] == 0: return 0 visited = [False]DDeloitte | COGNIZANT | IBM | CAPGEMINIdef maximizeQuality(cls, input1, input2, input3): n = input1 R = input2 P = input3 X = [] for b in range(32): mask = 1 << b contrib = 0 for val in P:

来自搜索索引的公开信息流 ChatCrawler ——“公开 Telegram 的 Google”;随着该社群被抓取而更新。 时间为 UTC。

仅限公开内容,使用 Telegram 官方 API。 关于 · 常见问题 · 索引限制 · 移除页面 · 目录 · 搜索 · 计算方法