Publicacióndef count_vowel_substring(input1):

def count_vowel_substring(input1): #write your code here v=set("aeiou") c=0 i=0 while i<len(input1): if input1[i] in v: j=i+1 while j<len(input1) and input1[j] not in v: j+=1 if j<len(input1): c+=1 i=j+1 else: break else: i+=1 return c Accenture✅