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TTishka1721:52ой, да

AAlexander T21:52>>> sum(1 for _ in range(10000) if any(x in ''.join(random.choices(['H', 'T'], k=100)) for x in ['H'*6, 'T'*6])) / 10000 0.7943 >>> sum(1 for _ in range(10000)

AAlexander T21:53кстати примерно 80% получается, хахахах

MMikael21:53🤔