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Thread pi = 22/7

3 messages · –
L
pi = 22/7 x1 = float(input("ertfa ostovane : ")) x2 = float(input("shoa ostovane : ")) x3 = pi * x2 * x2 *x1 print = ("dd",x3)
  1. T
    یک بار ادیتورت رو ببند و دوباره بازش کن بعدم دستور پرینت مساوی لازم نداره pi = 22 / 7 x1 = float(input("ertfa ostovane : ")) x2 = float(input("shoa ostovane : ")) x3 = pi * x2 * x2 * x1 print(x3)
    1. L
      اع اصلا به اون مساوی توجه نکرده بودم 🙈
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