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Post🚀 #Python: List Comprehension — qisqa, tez va samarali kod yozish usuli

7 November 2025
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Isoqjanov Ilyos | Python
🚀 #Python: List Comprehension — qisqa, tez va samarali kod yozish usuli Ko‘p hollarda ro‘yxat (list) yaratish uchun for siklidan foydalanamiz. Lekin Pythonda buni bitta qatorda yozish mumkin 😎 numbers = [i * 2 for i in range(5) if i > 0] print(numbers) 🧩 Bu kodda nima bo‘layapti? 1️⃣ for i in range(5) → i qiymatlari: 0, 1, 2, 3, 4 2️⃣ if i > 0 → faqat 1, 2, 3, 4 olinadi 3️⃣ i * 2 → har bir son 2 ga ko‘paytiriladi ✅ Natija: [2, 4, 6, 8] ⚡️ Nega List Comprehension foydali? ✅ 1. Kod qisqaradi # Oddiy usul nums = [] for i in range(5): if i > 0: nums.append(i * 2) # List comprehension nums = [i * 2 for i in range(5) if i > 0] 👉 Natija bir xil, lekin kod ancha ixcham va o‘qilishi oson. ✅ 2. Ishlash tezligi yuqori append() chaqiruvlari yo‘q, hammasi Pythonning ichki C darajasidagi optimallashtirilgan loopda bajariladi. Masalan: import time # Oddiy for start = time.time() nums = [] for i in range(10_000_000): nums.append(i * 2) print("Oddiy for:", time.time() - start) # List comprehension start = time.time() nums = [i * 2 for i in range(10_000_000)] print("List comprehension:", time.time() - start) 💡 Natija odatda 1.5–2 baravar tezroq bo‘ladi! ✅ 3. O‘qish oson va tushunarli even = [x for x in range(10) if x % 2 == 0] # Juft sonlar ro‘yxati ✅ 4. Filtrlash va o‘zgartirishni oson qiladi words = ["hello", "python", "world"] lengths = [len(w) for w in words] # [5, 6, 5] ✅ 5. Bir necha sikllarni birlashtirish Hatto bir nechta for ni bitta list comprehension ichida ishlatish ham mumkin: pairs = [(x, y) for x in [1, 2] for y in ['a', 'b']] # [(1, 'a'), (1, 'b'), (2, 'a'), (2, 'b')] 💬 Xulosa: 🔹 List comprehension — Pythonning eng qulay sintaksislaridan biri. 🔹 Kodni ixcham qiladi. 🔹 Ishlashni tezlashtiradi. 🔹 O‘qishni osonlashtiradi.
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