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21 February 2025
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DDeloitte | COGNIZANT | IBM | CAPGEMINIdef solve(N): sum_needed = (N * (N + 1)) // 2 k = ((N + 1) * (N + 2)) // 2 count = 0 total = 0 for i in range(N + 1, 0, -1): if total >= sum_needed: breakDDeloitte | COGNIZANT | IBM | CAPGEMINIBNY✅✅✅ Contact: @MLCODER2
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