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Postdef solution(crypt):

28 June 2025
D
Deloitte | COGNIZANT | IBM | CAPGEMINI
def solution(crypt): words = crypt x = list(set(''.join(words))) if len(x) > 10: return 0 first_letters = set(word[0] for word in words) d= {} ud = set() count = [0] def solve(word): return int(''.join(str(d[c]) for c in word)) def dfs(index): if index == len(x): for word in words: if d[word[0]] == 0: return if solve(words[0]) + solve(words[1]) == solve(words[2]): count[0] += 1 return char = x[index] for digit in range(10): if digit in ud: continue d[char] = digit ud.add(digit) dfs(index + 1) ud.remove(digit) del d[char] dfs(0) return count[0] //Triology✅ q1
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