Deloitte | COGNIZANT | IBM | CAPGEMINI@python_java_Coding · channel · 7 178 subscribers

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14 September 2025

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Deloitte | COGNIZANT | IBM | CAPGEMINI08:05def legoString(input1, input2, input3): wall = input1 n = input2 blocks = input3 if not wall or not blocks: return [-1] word_len = len(blocks[0]) if len(wall) <D

Deloitte | COGNIZANT | IBM | CAPGEMINI08:06def maxSumOfNonAdjacentNodes(cls, input1, input2): a = input2 n = len(a) if n == 0: return 0 eff = [0]*n for i in range(n): penalty = a[i-1] if i > 0 and a[i-1]

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