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Postdef find_equal_biomass_cut(input1, input2, input3):

15 September 2025
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Deloitte | COGNIZANT | IBM | CAPGEMINI
def find_equal_biomass_cut(input1, input2, input3): n = input1 biomass = input2 edges = input3 graph = [[] for _ in range(n)] for u, v in edges: graph[u].append(v) graph[v].append(u) total = sum(biomass) if total % 2 != 0: return [-1, -1] target = total // 2 valid_cuts = [] visited = [False] * n def dfs(node): visited[node] = True subtotal = biomass[node] for nei in graph[node]: if not visited[nei]: sub = dfs(nei) subtotal += sub if sub == target: valid_cuts.append(sorted([node, nei])) return subtotal dfs(0) if not valid_cuts: return [-1, -1] valid_cuts.sort() return valid_cuts[0] //Equal Biomass Partition✅✅
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